Project Euler Problem 6 Solution

Question

The sum of the squares of the first ten natural numbers is,

12+22+...+102=3851^2 + 2^2 + ... + 10^2 = 385

The square of the sum of the first ten natural numbers is,

(1+2+...+10)2=552=3025(1 + 2 + ... + 10)^2 = 55^2 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025385=26403025 - 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

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