Question
If we take 47, reverse and add, , which is palindromic.
Not all numbers produce palindromes so quickly. For example,
That is, 349 took three iterations to arrive at a palindrome.
Although no one has proved it yet, it is thought that some numbers, like 196, never produce a palindrome. A number that never forms a palindrome through the reverse and add process is called a Lychrel number. Due to the theoretical nature of these numbers, and for the purpose of this problem, we shall assume that a number is Lychrel until proven otherwise. In addition you are given that for every number below ten-thousand, it will either (i) become a palindrome in less than fifty iterations, or, (ii) no one, with all the computing power that exists, has managed so far to map it to a palindrome. In fact, 10677 is the first number to be shown to require over fifty iterations before producing a palindrome: 4668731596684224866951378664 (53 iterations, 28-digits).
Surprisingly, there are palindromic numbers that are themselves Lychrel numbers; the first example is 4994.
How many Lychrel numbers are there below ten-thousand?
NOTE: Wording was modified slightly on 24 April 2007 to emphasise the theoretical nature of Lychrel numbers.
Haskell
palindrome :: String -> Bool
palindrome s = s == reverse s
lychrel :: Int -> Bool
lychrel n = not $ any palindrome $ take 50 $ tail (iterate (\x -> show $ (read x) + (read $ reverse x)) (show n))
main :: IO ()
main = print $ length $ filter lychrel [1..10000]Python
#!/usr/bin/env python
def is_palindrome(s):
return s == ''.join(reversed(s))
def is_lychrel(n):
s = str(n)
i = 0
done = False
while not done:
if i > 50:
return True
s = str(int(s) + int(''.join(reversed(s))))
i += 1
if is_palindrome(s):
done = True
return False
def main():
count = 0
for n in range(10000):
if is_lychrel(n):
count += 1
print(count)
if __name__ == "__main__":
main()