Question
Using names.txt, a 46K text file containing over five-thousand first names, begin by sorting it into alphabetical order. Then working out the alphabetical value for each name, multiply this value by its alphabetical position in the list to obtain a name score.
For example, when the list is sorted into alphabetical order, COLIN, which is worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN would obtain a score of 938 * 53 = 49714.
What is the total of all the name scores in the file?
Haskell
import Data.List (sort)
parse :: String -> [String]
parse = words . map replaceComma . filter notQuote where
replaceComma ',' = ' '
replaceComma c = c
notQuote = (/= '"')
alphaIndex :: Char -> Int
alphaIndex c = fromEnum c - 64
alphaScore :: String -> Int
alphaScore = sum . map alphaIndex
totalScore :: [String] -> Int
totalScore names = sum $ zipWith (*) (map alphaScore $ sort names) [1..]
main :: IO ()
main = do
str <- readFile "/home/zach/code/euler/022/names.txt"
print $ totalScore $ parse str
Python
#!/usr/bin/env python
import os
from string import ascii_uppercase
def calculate_score(name, index):
alpha_score = sum(ascii_uppercase.index(letter)+1 for letter in name)
return index * alpha_score
def main():
names_file = open(os.path.join(os.path.dirname(__file__), 'names.txt'))
names_string = names_file.read()
names = [name.strip('"') for name in names_string.split(',')]
names.sort()
print(sum(calculate_score(name, index+1) for index, name in enumerate(names)))
names_file.close()
if __name__ == "__main__":
main()
Ruby
#!/usr/bin/env ruby
names = File.open(File.dirname(__FILE__) + '/names.txt').read.scan(/\w+/).sort
puts names.map { |name|
word_score = name.each_byte.map { |c| c - 64 }.reduce(:+)
(names.index(name) + 1) * word_score
}.reduce(:+)
Rust
fn main() {
let mut names: Vec<&str> = include_str!("names.txt").split(',').collect();
names.sort();
let sum: usize = names
.iter()
.enumerate()
.map(|(i, name)| {
let value: usize = name.chars()
.skip(1)
.take(name.len() - 2)
.map(|c| 1 + (c as usize) - ('A' as usize))
.sum();
(i + 1) * value
})
.sum();
println!("{}", sum);
}