## Project Euler Problem 28 Solution

## Question

Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows:

```
21 22 23 24 25
20 7 8 9 10
19 6 1 2 11
18 5 4 3 12
17 16 15 14 13
```

It can be verified that the sum of the numbers on the diagonals is 101.

What is the sum of the numbers on the diagonals in a 1001 by 1001 spiral formed in the same way?

## Haskell

```
main :: IO ()
main = print $ foldr (+) 1 [4*n^2 - 6*n + 6 | n <- [3,5..1001]]
```

```
$ ghc -O2 -o spiral spiral.hs
$ time ./spiral
real 0m0.001s
user 0m0.000s
sys 0m0.000s
```

## Python

```
#!/usr/bin/env python
def sum_diagonals_of_spiral(size):
n = 1
step = 2
total = 0
since_last = 0
while n <= size**2:
total += n
n += step
since_last += 1
if since_last == 4:
step += 2
since_last = 0
return total
print(sum_diagonals_of_spiral(1001))
```

```
$ time python3 spiral.py
real 0m0.035s
user 0m0.024s
sys 0m0.008s
```

## Ruby

```
#!/usr/bin/env ruby
i = 1
sum = i
step = 2
until i >= 1001**2
4.times { sum += i += step }
step += 2
end
puts sum
```

```
$ time ruby spiral.rb
real 0m0.036s
user 0m0.028s
sys 0m0.004s
```

Questions? Comments? Send me an email: [email protected]